Вводится матрица а(m,n) из 0 и 1. Найти в ней квадратную подматрицу из одних 1 максимального размера
Категория: C/C++
2011-09-16 23:23:15
code: #cpp
?#include#define bool int #define R 6 #define C 5 void printMaxSubSquare(bool M[R][C]) { int i,j; int S[R][C]; int max_of_s, max_i, max_j; /* Set first column of S[][]*/ for(i = 0; i < R; i++) S[i][0] = M[i][0]; /* Set first row of S[][]*/ for(j = 0; j < C; j++) S[0][j] = M[0][j]; /* Construct other entries of S[][]*/ for(i = 1; i < R; i++) { for(j = 1; j < C; j++) { if(M[i][j] == 1) S[i][j] = min(S[i][j-1], S[i-1][j], S[i-1][j-1]) + 1; else S[i][j] = 0; } } /* Find the maximum entry, and indexes of maximum entry in S[][] */ max_of_s = S[0][0]; max_i = 0; max_j = 0; for(i = 0; i < R; i++) { for(j = 0; j < C; j++) { if(max_of_s < S[i][j]) { max_of_s = S[i][j]; max_i = i; max_j = j; } } } printf("\n Maximum size sub-matrix is: \n"); for(i = max_i; i > max_i - max_of_s; i--) { for(j = max_j; j > max_j - max_of_s; j--) { printf("%d ", M[i][j]); } printf("\n"); } } /* UTILITY FUNCTIONS */ /* Function to get minimum of three values */ int min(int a, int b, int c) { int m = a; if (m > b) m = b; if (m > c) m = c; return m; } /* Driver function to test above functions */ int main() { bool M[R][C] = {{0, 1, 1, 0, 1}, {1, 1, 0, 1, 0}, {0, 1, 1, 1, 0}, {1, 1, 1, 1, 0}, {1, 1, 1, 1, 1}, {0, 0, 0, 0, 0}}; printMaxSubSquare(M); getchar(); }
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